

3% ($36,000) = $1,080 per year
$1,080 (10 years) = $10,800
$36,000 + 400 + 10,800 = $47,200
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The Simple Pay Back Period for an 84-kW system is found on Figure 6-8b, using $1685.70/kW, to be 6.8 years. This means that three turbines and three heat exchangers would be purchased. Figure 6-8a shows the annual utility savings to be $20,800. To find the internal rate of return on the investment (IRRI), use the following equation15:
Initial Investment + (Net Annual Savings)(P/A, IRRI, Y) = 0
where Y is the number of years that the system is assumed to last. Then the Discrete Compounding tables15 must be used to obtain P/A factors and these must be interpolated with their respective interest rates to find the IRRI. Typical system components last from 10 to 34 years1. Therefore, it is reasonable to calculate benefits over possible turbine lives of 10, 15 and 20 years. Using the cost of three turbines and therefore tripling the cost of maintenance:
$109,200 + (20,800 - 3,240)(P/A, IRRI, Y) = 0
(P/A, IRRI, Y) = 6.219
Note that this equation yields the actual pay back period15 of the investment, 6.2 years. The Discrete Compounding tables report the following:
(P/A, 9%, 10) = 6.4177 and (P/A, 10%, 10) = 6.1446
(P/A, 12%, 15) = 6.8109 and (P/A, 15%, 15) = 5.8474
(P/A, 15%, 20) = 6.2593 and (P/A, 18%, 20) = 5.3527
Therefore, linearly interpolating between P/A factors at Y = 10 years yields the following results:
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Interpolating between P/A factors at Y = 15 years gives an IRRI of 13.8%, and at Y = 20 years the rate of return is 15.1%.
20%($109,200) + (20,800 - 3,240 - loan payment)(P/A, IRRI, 10) = 0
Using a sample loan interest rate of 7%,
(A/P, 7%, 10) = 0.1424
And,
loan payment = 80%($109,200)(A/P, 7%, 10)
= 80%($109,200)(0.1424)
= $12,440.06
Also,
(P/A, IRRI, 10) = 4.266
Interpolating between (P/A, 18%, 10) = 4.4941 and (P/A, 20%, 10) = 4.1925 gives the result for this scenario, IRRI = 19.5%.
loan payment = $109,200(A/P, 7.5%, Y)
The A/P factors are found in the aforementioned Discrete Compounding tables15. A 10-year loan results in annual payments of $15,910.44. A 15-year loan costs $12,372.36 per year and a 20-year loan costs $10,717.98 per year. The loan payments are subtracted from the annual savings minus maintenance costs to obtain the net equivalent annual savings:
$20,800 - 3,240 - loan payment = equivalent annual savings
For the 10-year assumption, the equivalent annual savings is $1649.56, for the 15-year assumption it is $5187.64 and for the 20-year assumption $6842.02. Dividing each of these by 46.7 tons of carbon per year results, respectively, in profits of $35.32, $111.08 and $146.51 per ton of carbon over a 10-year, 15-year and 20-year life.